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how to display username that logged on into menu list?
etc:
Welcome John, menu1, menu2, menu3, logout

thanks in advanced

Customize ewmenu.php and echo CurrentUserName() above the menu.

can it be done on custom code?
not manually after the page has been generated

try this, it's working for me...

MenuItem_Adding server event:

 if ($Item->Id == -1 ) {
        if (IsSysAdmin() )
            $user="Administrator";
        else
            $user = $Security->CurrentUserInfo("vorname")." ".$Security->CurrentUserInfo("name"); // Note: change to your own field names in the user table
    
        if (IsLoggedIn() ) {       
            $Item->Text = '<img border="0" src="phpimages/door_in.png" width="12" height="12" align="top">&nbsp;<b>Logout</b>&nbsp;('.$user.')';
            $Item->ParentId = 18; // Account // Note: moves the "logout" to another menu-level, change to your own parent menu item ID
        }
}

NOTE: This piece of code moves the "logout" to another menu-level and is adding an icon and the name of the user.

i test it
its not working
and logout word is removed from menu

Customize template.php and add this :

<!-- header (begin) --><!-- *** Note: Only licensed users are allowed to change the logo *** -->

<div class="ewHeaderRow"><img src="phpimages/mylogo.png" alt="" border="0">
&nbsp;&nbsp;&nbsp;
<?php if (IsLoggedIn()) { ?>
<!-- display username -->
<span class="phpmaker"> Welcome: <? echo($_SESSION[EW_SESSION_USER_NAME]);?></span>

Try this in Menu_ItemAdding

after the }

type

if ( IsLoggedIn() )
{
echo "Hi, <b> ".CurrentUserInfo("Name");

}

just change the Name to your user field

thank you erzon
yes it's working fine but hi word repeat many

maybe you can post your code.. this code is working for me without any problem

thank you erzon

in server event

menuitem_adding

function MenuItem_Adding(&$Item) {
if ( IsLoggedIn() )
{
echo "Hi, <b> ".CurrentUserInfo("Name");

}

return TRUE;

}

in web appear
Hi jacson, Hi jacson, Hi jacson, Hi jacson, Hi jacson,Hi jacson, Hi jacson, Hi jacson, Hi jacson,

The server event menuitem_adding is called as many times as you have menu-items.

You need a logic wich show your echo only one time. Look at my first post!!!

jacson wrote:
i test it
its not working
and logout word is removed from menu

Hi Nicole,
thank you advance

You code Not work stop at line 26 > >> if (IsLoggedIn() ) {

You can fixed

Thank you again

put the code in Menu_Rendering and remove the return true statement it should work fine

Thank you all, this works fine for me:

function Menu_Rendering(&$Menu) {
if (IsLoggedIn()){
echo "Welcome back ".CurrentUserName();
}
}

You can add "Menu Editor", ex: user.

//function MenuItem_Adding

if (IsLoggedIn() ) {
$user = CurrentUserName();
if($Item->Text == 'user') {
$Item->Text = "Hi, <b>" . $user . "</b>";
}
}

cahilbey wrote:
Thank you all, this works fine for me:

function Menu_Rendering(&$Menu) {
if (IsLoggedIn()){
echo "Welcome back ".CurrentUserName();
}
}

IS WORK THANK YOU